An irregular object of mass 3 kg rotates about an axis, about which it has a radius of gyration of 0.2 m, with an angular acceleration of 0.5 rad. s? . the magnitude of the applied torque is: a) 0.30 n. m b) 3.0 x 102 n. m c) 0.15 n. m d) 7.5 x 102 n. m e) 6.0 x 102 n. m.

The magnitude of the applied torque is

(e) is correct option.

Explanation:

Given that,

Mass of object = 3 kg

Radius of gyration = 0.2 m

Angular acceleration = 0.5 rad/s²

We need to calculate the applied torque

Using formula of torque

Here, I = mk²

Put the value into the formula

Hence, The magnitude of the applied torque is

the force on the thing and the distance the force moves the thing