Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. find the acceleration at 3 seconds. b. find the displacement at 2 seconds.

a.

b.

Explanation:

Given:

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

At time t = 3 seconds,

Note: The arguments of the sine is calculated in unit of radian and not in degree.

The velocity of the particle at some is defined as the rate of change of the position of the particle.

For the time interval of 2 seconds,

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

It is the displacement of the particle in 2 seconds.

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.

talk back to him about the sport and show him your expertise or leave the room