Asurface charge distribution is described by f=aoz s2 sin(o), where ao is a constant. find the total charge under the following conditions: a) the charge is distributed over the surface of a cylinder with radius 'r' and length 'l'. (the surface looks like a (unopened) coke can) b) the charge is distributed over the top and bottom surface of a wedge with radius 'r', height 'h', and circumference which is 1/8th the circumference of a circle with radius 'r'. (a 'wedge' looks like a slice of pizza. you can assume o starts at 0).

Which units can be used to measure length or distance? check all that apply. gram meter kilometer liter inch

Jason and mia are both running in a race. as they approach the finish line, you being the physicist that you are decide to time how long it takes them to reach the end of the race. when you start your stop watch (you can take this as time t = 0 s) you notice that mia is an unknown distance d ahead of jason and both are moving with the same initial velocity v_0. you also notice that jason is accelerating at a constant rate of a_j, while mia is deaccelerating at a constant rate of -a_m. jason and mia meet each other for the first time at time t = t_1. at this time (t = t_1) jason's velocity is two times that of mia's velocity, meaning v_j (t_1) = 2v_m (t_1). a) draw the position vs. time graph describing mia's and jason's motion from time t = 0 to time t = t_1. clearly label your axes and initial conditions on your graph. b) draw the velocity vs. time graph describing mia and jason's motion from time t = 0s to time t = t_1. clearly label your axes and initial conditions on your graph. c) how long from when the stop watch was started at t = 0s did it take mia and jason to meet? express your answer in terms of know quantities v_0, a_m, and a_j. d) when the stop watch started at time t = 0s, how far apart, d, were mia and jason? express your answer in terms of know quantities v_0, a_m, and a_j.

What is the earliest point in the universe that we can observe? why can’t we see back further than this?