The constant forces f1 = 8 + 29 + 32 n and f2 = 48 - 59 - 22 n act together on a particle during a displacement from the point a (20, 15,0)m to the point b (0,07) m. what is the work done on the particle? the work done is given by f. f, where is the resultant force (here f = fi + f2) and is the displacement.

- 600 J

Explanation:

A (20, 15, 0 ) m

B (0, 0, 7) m

Net force

Work done is defined as

W = -1120 + 450 + 70

W = - 600 J

pe = weightxheight = 2000x1000=2,000,000joules

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards