Evaluate the integrals (a) s (3x2 – 2x – 1) 5(x – 3)d. (b) write an expression for the volume charge density p(r) of a point charge q at the specific position) r' and very that the volume integral saul space p(r)dt is equal to q (c) a spherical shell of charge with radius r is described by the charge distribution par) = a8(r – r) where a is a constant. assuming the total charge of the shell is q, find the constant a.

The answer would be a) -80of

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Hey did u get the answer?