An object is placed a distance of 20 cm from a convex mirror of radius 40 cm. how far (in cm) is the image from the mirror?

Be sure you understand two optics principles: the focal length of a convex mirror is NEGATIVE (by convention) and R / 2 = f.

Find f, take its negative, plug in the mirror equation and obtain Di = - 24 cm. This indicates that the image is virtual (as it should be in a convex mirror), is erect (as all virtual images are), is diminished (as it should be) and INSIDE the mirror as it should be.

Explanation:

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j