Two positive point charges with charges q1 and q2 are separate by a distance of 30cm. a third positive charge qo is placed between the two charges at 8cm on the right of the charge q1. see picture. the charge qo is equal to 3 µc (micro-coulombs = 10-6 c). the coulomb force exerted by q1 on qo is 25 n and the coulomb force exerted by q2 on qo is 10 n. determine the net electric field in magnitude and direction on the charge qo due to the other two charges.

The magnitude of net electric is from charge to along the line joining them.

Explanation:

Given:

Distance between the charges =30 cm

Magnitude of charge

Force exerted by on =25 N

Force exerted by on =10 N

Now according to coulombs Law we have

similarly

Noe the electric field at eh position of charge is given by

Let  be the electric field due to charge   and   bet he electric field due to charge  

then The net electric Field at the point is given by

The direction of electric Field is from charge to along the line joining them.

answer: electrons