Aplane takes off from an airport and flies to town a, located d1 = 335 km from the airport in the direction 20.0° north of east. the plane then flies to town b, located d2 = 245 km at 30.0° west of north from town a. use graphical methods to determine the distance and direction from town b to the airport. (enter the distance in km and the direction in degrees south of west.)

R = 545.38 m ; θ = 28.43°

Explanation:

given,

for town A : d₁ = 335 km at an direction of 20° north of east

for town B : d₂ = 245 km at  30.0° west of north from town A

x = 335 cos 20° + 245 sin 30°

x = 437.29 m

y = 335 sin 20° + 245 cos 30°

y = 326.75 m

R = 545.38 m

θ = 28.43°

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s