Ship a is located 4.2 km north and 2.7 km east of ship b. ship a has a velocity of 22 km/h toward the south and ship b has a velocity of 39 km/h in a direction 36 â° north of east. what are the (a) x-component and (b) y-component of the velocity of a relative to b?

(a) The x-component of velocity is 31.55 km/h

(b) The y-component of velocity is 44.92 km/hr

Solution:

As per the solution:

The relative position of ship A relative to ship B is 4.2 km north and 2.7 km east.

Velocity of ship A, = 22 km/h towards South =

Velocity of ship B, = 39 km/h Towards North east at an angle of =

Now, the velocity of ship A relative to ship B:

Now,

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it