a chlorine atom has 7 valence electrons in its third shell.
what will it do when forming an ion?

The chlorine atom will accept a lone pair of electron from another element in other to complete its outermost shell

Explanation:

The chlorine atom will accept a lone pair of electron from another element in other to complete its outermost shell.

Chlorine being an unstable element will accept a lone pair of electron from another element like sodium to form a negatively charged ion(acceptor) thereby becoming stable. Sodium being the donor will easily donate its lone pair of electron to chlorine through covalent bonding thereby becoming the donor and forming a positively charged ion(Na+).

Note that for an element to be stable, such element may have a obey the duplet or octet rule I.e must possess 2 electrons or 8 electrons in its outermost shell.

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

the entire statement is true and correct.  

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