During a baseball game, a batter hits a high
pop-up.
if the ball remains in the air for 6.37 s, how
high does it rise? the acceleration of gravity
is 9.8 m/s2.

50.0 m

Explanation:

First of all, we can find the initial velocity of the ball, using the equation

v = u + at

where

v = 0 is the velocity of the ball at the highest position

u is the initial velocity

is the acceleration of gravity

is the time the ball took to reach the maximum height (half of the time it remained in the air)

Solving for u,

Now we can find the maximum height using the other SUVAT equation:

where d is the maximum height. Solving for d,

where are the vectors ?

the answer for apex is the lowest