Acarousel that is 5.00 m in radius has a pair of 600-hz sirens mounted on posts at opposite ends of a diameter. the carousel rotates with an angular velocity of 0.800 rad/s. a stationary listener is located at a distance from the carousel. the speed of sound is 350 m/s. the longest wavelength reaching the listener from the sirens is closest to

The answer is about 0,59 m or 59 cm the longest wavelength for a listener when the sirens is closest.

Explanation:

Using the equation of the effect Doopler:

Replacing:

W angular velocity  = 0,8

V = 350

VL = 0 * 5 m

Vs = 4  

Replacing:

Note: Notice, the division have the same units so, it can be simplify

Now using the frequency f' as the frequency of the listener to know L wavelength as the relation between f' and V

Note: Remember Hz units are relations inverse of time so:

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

h o h o hope you have a merry christmas!