A5kg object is released from rest near the surface of a planet such that its gravitational field is considered to be constant. the mass of the planet is unknown. after 2s, the object has fallen 30m. air resistance is considered to be negligible. what is the gravitational force exerted on the 5kg object near the planet’s surface?

75 N

Explanation:

t = Time taken = 2 seconds

u = Initial velocity

v = Final velocity

s = Displacement = 30 m

a = Acceleration

The acceleration due to gravity on the planet is 15 m/s²

Force

F = ma

The gravitational force exerted on the object near the planet’s surface is 75 N

like poles repel so keep pushing north to north and repels funny to see this

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2