(a)a soccer player kicks a rock horizontally off a 35 m high cliff into a pool of water. if the player hears the sound of the splash 2.83 s later, what was the initial speed given to the rock (in m/s)? assume the speed of sound in air is 343 m/s.(b)what if? if the temperature near the cliff suddenly falls to 0°c, reducing the speed of sound to 331 m/s, what would the initial speed of the rock have to be (in m/s) for the soccer player to hear the sound of the splash 2.83 s after kicking the rock?

a)v=15.83 m/s

b)v=14.89 m/s

Explanation:

a)

In y direction

Given that h=35 m and initial velocity is zero.

So

t=2.67 sec

It means that rock hit water after 2.61 sec.

Given that player hears after 2.83 sec.

Δt=2.83 - 2.67 s

Δt=0.16 sec

So distance travel by sound wave

d= C x Δt

C= 343 m/s

d= 343 x 0.16

d=54.88 m

From diagram

x=42.27 m

Now

x = v x  t

v=42.27/2.67

v=15.83 m/s

b)

Now sound speed have been changed

So new d

d=331 x 0.16

d=52.96 m

New x

x=39.75

So new velocity v

v=x/t

v=39.75/2.67

v=14.89 m/s

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation:

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