Askier is accelerating down a 30.0 degree hill at 3.80 m/s2. how long (in seconds) will it take her to reach the bottom of the hill, assuming she starts from rest and accelerates uniformly, if the elevation change is 130 m?

t = 11.69s

Explanation:

The distance traveled by the skier is given by:

  where H=130m

D = 260m

Now, the movement down the hill is described by:

 Solving for t:

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.