Two charged particles, q1 and q2, are located on the x-axis, with q, at the origin and q, initially at x1 = 18.8 mm. what is the force (magnitude and direction) that q2 exerts on q, at this new location? (give the magnitude in hn.) = 12.0 mm. in this configuration, q1 exerts a repulsive force of 2.62 un on q2. particle q2 is then moved to x2 magnitude direction -select-

Suppose you were asked to find the torque about point p due to the normal force n in terms of given quantities. which method of finding the torque would be the easiest to use?

To do work, this truck uses energy stored in chemical fuel and an electrical battery. how much total energy does this truck put out?

Part f - example: finding two forces (part i) two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. the block in (figure 1) has a mass m=10kg and is being pulled by a force f on a table with coefficient of static friction îľs=0.3. four forces act on it: the applied force f (directed î¸=30â above the horizontal). the force of gravity fg=mg (directly down, where g=9.8m/s2). the normal force n (directly up). the force of static friction fs (directly left, opposing any potential motion). if we want to find the size of the force necessary to just barely overcome static friction (in which case fs=îľsn), we use the condition that the sum of the forces in both directions must be 0. using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as: fcosî¸â’îľsn=0 fsinî¸+nâ’mg=0 in order to find the magnitude of force f, we have to solve a system of two equations with both f and the normal force n unknown. use the methods we have learned to find an expression for f in terms of m, g, î¸, and îľs (no n).