If an electron is accelerated from rest through a potential difference of 9.9 kv, what is its resulting speed? (e = 1.60 × 10-19 c, k = 1/4πε0 = 8.99 × 109 n · m2/c2, m el = 9.11 x 10-31 kg) if an electron is accelerated from rest through a potential difference of 9.9 kv, what is its resulting speed? ( = 1.60 × 10-19 c, = 1/4π = 8.99 × 109 n · m2/c2, el = 9.11 x 10-31 kg) 4.9 × 107 m/s 3.9 × 107 m/s 2.9 × 107 m/s 5.9 × 107 m/s

So speed of electron will be

Explanation:

We have given potential difference V = 9.9 KV

Charge on electron

So energy of electron

This energy of electron will be equal to kinetic energy of electron

So

So speed of electron will be

absorption lines are where light has been absorbed by the atom thus you see a dip in the spectrum whereas.

emission spectra have spikes in the spectra due to atoms releasing photons at those wavelengths.

explanation: