You are launching a 2 kg potato out of a potato cannon. the cannon is 1.1 m long and is aimed 65 degrees above the horizontal. it exerts a 48 n force on the potato. what is the kinetic energy (in j) of the potato as it leaves the muzzle of the potato cannon?

51.84

Explanation:

Given

cannon is 1.1 m long

Force on potato is 48 N

angle of launch

Net force at the end of cannon

65-mgsin(65)=65-17.78=47.21 N

acceleration is given by

Velocity acquired during travel of 1.1 m

v=7.20 m/s

kinetic energy of the potato

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s