Adelta connected load with each z = 8 30degree ohms is supplied from a balanced three phase wye connected generator through lines having series impedance of 0.25 30degree ohms. the line-to-line voltage measured at the load is 208 volts (for the angle, use load vab as the reference, such that vab = 208 0degree volts). calculate the three load phase currents (magnitude and angle). calculate the magnitude of the line-to-line voltage at the generator. calculate the power factor at the generator (be sure to indicate leading or lagging).

This is the answer: body 1 + engine 2

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Distance covered, s = 8ft - 4ft = 4 ftinitial velocity, u = 34 ft/sthe acrobat is moving upwards and therefore, a = -g = -9.81 m/s^2 = 32.19 ft/s^2applying equation of motion; s = ut -1/2gt^2then,4 = 34t -1/2*32.19t^24 = 34t - 16.095t^2rearranging; -16.095t^2 + 34t - 4 = 0solving the quadratic equation; t = {-34 +/- sqrt [34^2 - 4(-16.)]}/2(-16.095) = 1.06 +/- 0.93 = 0.13 or 1.99the acrobat will take 0.13 seconds to be at 8 ft above the ground. additionally, once at the maximum height, the acrobat will move down and be at the same spot (that is height) after 1.99 seconds moving down.