A3.05 kg block is sliding across level ground with uk=0.250. what is the friction force? (unit=n)

7.48 N

Explanation:

Friction force equals the normal force times the coefficient of friction.

F = Nμ

For a block on level ground, the normal force equals the weight.

N = mg

Therefore:

F = mgμ

F = (3.05 kg) (9.81 m/s²) (0.250)

F = 7.48 N

power out to power in less than 100%

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer