Acar goes 4 m/s for 10 seconds then speeds up to 12 m/s in
two seconds. the car continues at this speed for a minute. the car then
accelerates at -3 m/s" for 10 seconds
how far did the car go in each time interval?

Explanation:

For 10 seconds, v= d/t

4= d/10

d = 4×10= 40m

For 2 seconds,

V=d/t

12 =d/2

d =12 × 2 =24m

For the last 10 seconds,

S = ut +1/2 at^2

S = 0×10 + 1/2 × - 3 ×10^2

S=-150m

1 the 4 is sig

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y