Aphysics student stands on the rim of the canyon and drops a rock. the student measures the time for it to reach the bottom to be 3.2 seconds how deep is the canyon

50.2 m

Explanation:

We can solve the problem by using the following SUVAT equation for the vertical position of the rock:

where

h is the initial height (the depth of the canyon), taking the bottom of the canyon as reference position

u = 0 is the initial velocity of the rock

t is the time

is the acceleration of gravity

When the rock reaches the bottom, t = 3.2 s and y = 0. Substituting these numbers and solving for h, we find the depth of the canyon:

multiple

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge