An electric field of magnitude s.25 105 n/c points due south at a certain location. find the magnitude and direction of the force on a-6 charge at this location.

F=3.15 N pointing south

Explanation:

For the magnitude:

For the direction:

In the equation F=qE, both F and E are vectors while q is the module of the charge, this means that the direction of the electric field is the one that gives the direction of the force, in this case both point south

the independent variable, or the one that is intentionally manipulated is the speed.