Physics, 04.10.2019 21:30 emma042902

Afly lands on one wall of a room. the lower-left corner of the wall is selected as the origin of a two-dimensional car- tesian coordinate system. if the fly is located at the point having coordinates (2.00, 1.00) m, (a) how far is it from the origin? (b) what is its location in polar coordinates?

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Answer from: natcooper6204

a) The fly is 2.24 m from the origin.

b) In polar coordinates, the position of the fly is (2.24 m, 26.7°).

Explanation:

Hi there!

The position vector of the fly is r = (2.00, 1.00)m. The distance from that point to the origin is the magnitude of the vector "r" (see figure).

a) Notice in the attached figure that the distance from the origin to the point where the fly is located is the hypotenuse of the triangle formed by r, the x-component of r (2.00 m) and the y-component ( 1.00 m). Then:

r² = (2.00 m)² + (1.00 m)²

r² = 5.00 m²

r = 2.24 m

The fly is 2.24 m from the origin.

b) To find the angle θ (see figure) we can use trigonometry:

cos θ = adjacent / hypotenuse

cos θ = 2.00 m / √5 m

θ = 26.7°

The same will be obtained if we use sin θ:

sin θ = opposite / hypotenuse

sin θ = 1.00 m / √5 m

θ = 26.7°

In polar coordinates, the position of the fly is (2.24 m, 26.7°).

Afly lands on one wall of a room. the lower-left corner of the wall is selected as the origin of a t

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

spare some change and give it to the poor

explanation:

plz : ((

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