The gauge pressure in your car tires is 2.50 x 105 n/m^2 at a temperature of 35.0ºc when you drive it onto a ship in los angeles to be sent to alaska. what is their gauge pressure on a night in alaska when their temperature has dropped to -40.0ºc? assume the tires have not gained or lost any air

the new ppresure 1.89 10⁵ Pa

Explanation:

In this case we assume that the air is compiled as an ideal gas, which is described by the expression

       P V = nR T

Where P is the pressure and T is the absolute temperature, let's write this expression for the two points that tell us

     P1 = (nR / V) T1

     P1 / T1 = nR / V

     P2 = (nR / V) T2

     P2 / T2 = nR / V

With the constant on the right side is the same we can match the two equations

    P1 / T1 = P2 / T2

Let's take the tempera to absolute

     T1 = 35.0 + 273.15

     T1 = 308.15K

     T2 = -40.0 + 273.15

     T2 = 233.15K

Let's clear and calculate the pressure (P2)

      P2 = P1 T2 / T1

      P2 = 2.50 10⁵ 233.15 / 308.15

      P2 = 1.89 10⁵ Pa

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2