Acharge of -3.40 nc is placed at the origin of an xy-coordinate system, and a charge of 2.45 nc is placed on the y axis at y = 4.25 cm . a. if a third charge, of 5.00 nc , is now placed at the point x = 2.90 cm , y = 4.25 cm find the x and y components of the total force exerted on this charge by the other two charges.
b. find the magnitude of this force.
c. find the direction of this force.

The magnitude of this force is

The direction of this force is 55.69°.

Explanation:

Given that,

Charge at origin

Charge at y axis

Distance on y axis = 4.25 cm

Third charge

Distance on x axis = 2.90 cm

(a). We need to calculate the force F₁₃  

Using formula of force

Put the value into the formula

We need to calculate the force F₁₂  

Using formula of force

Put the value into the formula

The magnitude of this force is

The total force exerted on this charge by the other two charges.

Here,

Put the value into the formula

(c). We need to calculate the direction of this force

Using formula of direction

Put the value into the formula

Hence, The magnitude of this force is

The direction of this force is 55.69°.

answer: good job it's all correct !

explanation:

temp rises, and expansion