An object propelled upwards with an acceleration of 2.0 m / s ^ 2 is launched from rest. after 6 seconds the fuel runs out. determine the speed at this time and the maximum height at which it reaches.

43.34 m

Explanation:

Given

acceleration(a)

Initial Velocity(u)=0 m/s

After 6 s fuel runs out

Velocity after 6 s

v=u+at

After this object will start moving under gravity

height reached in first 6 s

s=36 m

After fuel run out distance traveled in upward direction is

here v=0

u=12 m/s

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27