An airplane has a mass of 3.1x10^4 kg and takes off under the influence of a constant net force of 3.7x10^4 n. what is the net force that acts of the plane's 78-kg pilot?

Net force that acts on the pilot = 93 N (rounded off to nearest 1 N)

Explanation:

An airplane has a mass of 3.1 × Kg

The applied force for it to take off = 3.7 × N

According to Newton's second law of motion; applied force (F) is directly proportional to the product of mass (M) and acceleration (A) of the object.

i.e F ∝ MA

This means that the applied force (F) is also directly proportional to the mass (M) of the object.

i.e F ∝ M

Acceleration (A) in this case is constant.

If the airplane's mass = 3.1 × kg requires 3.7 × N to take off,

Then the pilot's mass of 78 kg will require;

= 93.09677419 N = 93N (rounded off to nearest 1 N)

none, its a machine

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