An airplane has a mass of 3.1x10^4 kg and takes off under the influence of a constant net force of 3.7x10^4 n. what is the net force that acts of the plane's 78-kg pilot?

93.10 N

Explanation:

Given mass of plane = 3.1x10^4 kg

Constant net force of plane=  3.7x10^4 N

Mass of pilot is the plane = 78 kg

Find the acceleration of the plane;

Force is product of mass and acceleration.

F=ma where m is mass of plane, a is acceleration of the plane and F is net force of plane

F=ma

37000=31000*adivide both sides by 31000

37000/31000=a

1.194 m/s²=a

Now find the Net force on the pilot as

Fnet on pilot= mass of pilot by acceleration of the pilot

Acceleration of the pilot=acceleration of plane

Fnet=m*a

Fnet= 78*1.194 = 93.10 N

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

answer a fan shaped mass of sediment deposited at the base of a mountain front do to an abrupt change in stream gradient;