The total charge a battery can supply is rated in ma⋅h , the product of the current (in ma ) and the time (in h ) that the battery can provide this current. a battery rated at 1000 ma⋅hr can supply a current of 1000 ma for 1.0 h , 500 ma current for 2.0 h , and so on. a typical aa rechargeable battery has a voltage of 1.2 v and a rating of 1800 ma⋅h . part a for how long could this battery drive current through a long, thin wire of resistance 34 ω ? express your answer in hours. δt δ t = nothing h submitrequest answer provide feedback next

0.2  hours

Explanation: In order to solve this question we have to considerer that a recargeable battery can supply 1800 mA  in one hour then we have to determine how long could this battery drive current through a long, thin wire of resistance 34 Ω .

Besides, this battery has a voltage of 12 V

so by using the Ohm law we also know that V=R*I,

Fron this we can obtain:

I= V/R= 12 V/ 34 Ω=0.35 A= 350 mA

then considering that this battery can supply 1800 mA in one hour we have this battery can supply 350 mA  in x time in the form:

1hour 1800 mA

x hour350 mA

time= 350/1800= 0.2 hour

adding a(n) to an electric circuit would increase the magnetic field around a wire;

b. solenoid

a solenoid is a type of electromagnet whose purpose is to generate a controlled magnetic field.

if the purpose of the solenoid is instead to impede changes in the electric current, a solenoid can be more specifically classified as an inductor rather than an electromagnet.