Amajor-league catcher gloves a 92 mi/h pitch and brings it to rest in 0.15 m. if the force exerted by the catcher is 803 n, what is the mass of the ball?

0.14 kg

Explanation:

a= (Vf²- Vi²)/2.d

the final velocity is 0 (rest), and the initial velocity is 92 mi/h, that is equal to 41 m/s and the distance is 0.15 meters.

a= -5603 m/s² the minos means that the object is decelerating.

then we can use the second Newton law

F= m.a

m= F/a > m= 803N / 5603 m/s²

m= 0.14 kg

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