Daniel takes his two dogs, pauli the pointer and newton the newfoundland, out to a field and lets them loose to exercise. both dogs sprint away in different directions while daniel stands still. from daniel's point of view, newton runs due north at 3.90 m/s, but from pauli's point of view, newton appears to be moving at 1.10 m/s due east. what is pauli's velocity relative to daniel, ⃗ pd?

4.05 m/s

Explanation:

We shall represent the different velocity in vector form

Newton runs due north at 3.90 m/s, with respect to standing Daniel .

V_n = 3.9 j

Let Pauli runs with respect to standing Daniel with velocity X .

Then relative velocity of Newton with respect to running Pauli will be

3.9 j - X

Give that

relative velocity of Newton with respect to running Pauli = 1.1 i ( 1.1 due east )

So

3.9 j - X = 1.1 i

X =  -1.1 i + 3.9 j .

Magnitude of X

X² = 1.1 ² + 3.9²

X = 4.05 m/s

So Pauli runs with respect to standing Daniel with velocity 4.05 m /s .

Direction will be ,  west of north at angle θ ,

Tan θ = 1.1 / 3.9

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .