Aball is thrown horizontally from the top of a 60.0-m building and lands 100.0 m from the base of the building. ignore air resistance.

(a) how long is the ball in the air?
(b) what must have been the initial horizontal component of the velocity?
(c) what is the vertical component of the velocity just before the ball hits the ground?
(d) what is the velocity (including both the horizontal and vertical components) of the ball just before it hits the ground?

Explanation:

Given

height of building (h)=60 m

Range of ball=100 m

(a)time travel to cover a vertical distance of 60 m

t=3.49 s

(b)To cover a range of 100 m

R=ut

(c)vertical component of velocity just before it hits the ground

(d)

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s