A160 pf capacitor and a 640 pf capacitor are both charged to 1.8 kv. they are then disconnected from the voltage source and are connected together, positive plate to positive plate and negative plate to negative plate.

(a) find the resulting potential difference across each capacitor.

(b) find the energy lost when the connections are made.

a). The resulting potential difference across each capacitor is 1.8 kV.

(b). The energy lost  is zero.

Explanation:

Given that,

First capacitor = 160 pF

Second capacitor = 640 pF

Voltage = 1.8 kV

(a). We need to calculate the initial charge

Using formula of charge

Put the value into the formula

We need to calculate the final charge

Using formula of charge

The total charge is

We need to calculate the resulting potential difference across each capacitor

Using formula of potential difference

Put the value into the formula

(b). We need to calculate the energy lost when the connections are made

Using formula of energy

Put the value into the formula

Hence, (a). The resulting potential difference across each capacitor is 1.8 kV.

(b). The energy lost  is zero.

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

v patient student

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .