As a 5.0 x 10^2 newton basketball player jumps from the floor up toward the basket, the magnitude of the force of her feet on the floor is 1.0 x 10^3 newtons. as she jumps, the magnitude of the force of the floor on her feet is
1) 5.0 x 10^2 n
2) 1.0 x 10^3 n
3) 1.5 x 10^3 n
4) 5.0 x 10^5 n

2) 1.0 x 10^3 N

Explanation:

As a 5.0 x 10^2 newton basketball player jumps from the floor up toward the basket, the magnitude of the force of her feet on the floor is 1.0 x 10^3 newtons. As she jumps, the magnitude of the force of the floor on her feet is

1) 5.0 x 10^2 N

2) 1.0 x 10^3 N

3) 1.5 x 10^3 N

4) 5.0 x 10^5 N

The answer is B , because from newton's third law of motion which states that action and reaction are equal and opposite.

so the reaction of the floor on her leg will be equal to the the magnitude of her feet on the floor, this will hold if the floor does not collapse.

we need to know the time interval during which the force acts. impulse of force = momentum change