Adockworker applies a constant horizontal force of 73.0 n to a block of ice on a smooth horizontal floor. the frictional force is negligible. the block starts from rest and moves a distance 13.0 m in a time 4.50 s.(a)what is the mass of the block of i found this to be 56.9kg and got it right.(b)if the worker stops pushing at the end of 4.50 s, how far does the block move in the next 4.20s ?

(a) Mass of the car will be 56.8285 kg

(b) Distance traveled in next 4.20 sec will be 33.9619 m

Explanation:

We have given horizontal force F = 73 N

As it is given that the block starts from the rest so initial velocity u = 0 m/sec

Distance traveled s = 13 m

Time t = 4.5 sec

(a) From second equation of motion

Now according to newton second law force F = ma

So mass

(b) Velocity after 4.20 sec v = u+at

v=0+1.2839×4.20 = 5.39 m/sec

So initial velocity for second case = 5.39 m/sec

From second equation of motion

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

the assestment will probley apele with cause and effect