The kentucky derby is held at the churchill downs track in louisville, kentucky. the track is one and one-quarter miles in length. one of the most famous horses to win this event was secretariat. in 1973 he set a derby record that has never been broken. his average acceleration during the last four quarter-miles of the race was +0.0105 m/s2. his velocity at the start of the final mile was about +16.58 m/s. the acceleration, although small, was very important to his victory. to assess its effect, determine the difference between the time he would have taken to run the final mile at a constant velocity of +16.58 m/s and the time he actually took. although the track is oval in shape, assume it is straight for the purpose of this problem. number units

2.815 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Time taken with the acceleration is 94.25 seconds

Time = Distance / Speed

Difference in time = 97.065-94.25 = 2.815 seconds

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.