If an object is given an initial velocity straight upward of v 0 feet per second from a height of s 0 feet, then its altitude s after t seconds is given by the formula upper s equals negative 16 t squared plus v 0 t plus s 0 . an arrow is shot upward with a velocity of 112 feet per second from an altitude of 14 feet. for how many seconds is this arrow more than 174 feet high?

3 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 32 ft/s²

174 feet from the ground is 174-14 = 160 ft from the launch area

When the arrow will reach the 160 ft point while returning the initial velocity becomes equal to the final velocity which means the time taken to come down also becomes equal.

Hence, the arrow will be 1.5+1.5 = 3 seconds above a height of 174 ft from the ground.

a 2,000 calorie based diet.

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

                                              ⇒      

here   k is the proportionality constant whose value is 1.

                                                            [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.