Consider two small masses of air, both at a pressure of 1000 mb. one mass is on the beach in costa rica (lucky air mass) and the other is on a glacier in greenland ( which mass has the higher density?

the air density in Costa Rica is less than the air density in Greenland

Explanation:

Analyze this case give us information about air that in the first approximation we can consider it an ideal gas, so we can use the equation

     PV = nRT

Where P is the pressure is the volume, n the number of moles, T the absolute temperature

They ask us to calculate the density with formula

     d = m / V

Of  the first equation

      n / V = (P / R) 1 / T (1)

The number of moles is directly related to the mass of the gas, therefore the ratio of the left (n / V) is proportional to the density of the gas

Let's analyze there are several constant quantities, the pressure. The area of Costa Rica is close to the Earth's equator, so it has a high temperature (T1). The part of Greenland is near the Arctic circle cooler zone (T2). Therefore the temperature of Costa Ricacha is much higher than that of Greenland (T1 >> T2)

In equation 1 we see that as the density is inversely proportional to the temperature, therefore the air density in Costa Rica is less than the air density in Greenland

vapour or gas assuming atmospheriv pressure

the right answer is 0.3 meters per second