Tarzan, who weighs 849 n, swings from a cliff at the end of a 18.0 m vine that hangs from a high tree limb and initially makes an angle of 26.9° with the vertical. assume that an x axis points horizontally away from the cliff edge and a y axis extends upward. immediately after tarzan steps off the cliff, the tension in the vine is 757 n. just then, what are (a) the force from the vine on tarzan in unit-vector notation, and (b) the net force acting on tarzan in unit-vector notation? what are (c) the magnitude and (d) the direction (measured counterclockwise from the positive x-axis) of the net force acting on tarzan? what are (e) the magnitude and (f) the direction of tarzan's acceleration just then?

Part a)

Part b)

Part c)

Part d)

Part e)

Part f)

Explanation:

Part a)

Magnitude of tension force is given as

at 26.9 degree with vertical

Part b)

Net force on Tarzen is given as

Part c)

magnitude of the force is given as

Part d)

Direction of the force is given as

Part e)

Magnitude of the acceleration

tex]a = \frac{384.2}{86.5}[/tex]

Part f)

Direction of acceleration is same as the direction of the force

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increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.