Three point charges have equal magnitudes, two being positive and one negative. these charges are fixed to the corners of an equilateral triangle, as the drawing shows. the magnitude of each of the charges is 4.5 μc, and the lengths of the sides of the triangle are 1.0 cm. calculate the magnitude of the net force that each charge experiences.

Explanation:

Given

magnitude of charge=4.5\nu C

length of side of triangle=1 cm

There are two Positive charge and one negative charge

So net Force on negative charge is

sum of

where =force exerted by first positive charge on negative charge

=force exerted by second positive charge on negative charge

Two are at an angle of 60 (as it is placed at a corner of equilateral triangle)

Force Experienced by a positive charge will be of attractive and repulsive in nature

Two Forces are at an angle of 120 therefore

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer