In tests on earth a lunar surface exploration vehicle (mass=5.90*103 kg) achieves a forward acceleration of 0.220m/s2. to achieve this same acceleration on themoon, thevehicle's engines must produce a drive force of 1.43*103n. what is the magnitude of the frictional force that acts on thevehicle on the moon? all i know is it has something to do with the formulag=m1m2/r2. i figure the thefrictional force is th force opposing the drive force..i figured it out !

132 N

Explanation:

m = Mass

a = Acceleration

F = ma

Force on Earth

Force on Moon

Here, the effect of gravity is already compensated by the forces hence gravity will not have any effect.

Frictional force would be the difference between the two forces

Frictional force is 132 N.

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)