The filament of a lightbulb has a resistance of r0=12ω at 20 ∘c and 140 ω when hot. part apart complete part b in this temperature range, what is the percentage change in resistance due to thermal expansion? express your answer using two significant figures. rexpansion−r0r0r e x p a n s i o n − r 0 r 0 = 1100 %

T = 2390 degree C

Explanation:

Given data:

Resistance 12 ohm

Temperature 20 degree C

we know that linear relation between the resistance and temperature is given as

where is resistance at and = coefficient of resistivity

SOLVING FOR

degree C

WE KNOW

T = 2370 + 20

T = 2390 degree C

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6

3.2x10^7