Ajet airliner moving initially at 3.00 3 102 mi/h due east enters a region where the wind is blowing 1.00 3 102 mi/h in a direction 30.0° north of east. (a) find the components of the velocity of the jet air- liner relative to the air, svja. (b) find the components of the velocity of the air relative to earth,

a) Vaw = 2.19 mi / h  θ = 346.8º b) Vmgx = 0.866 mi / h   Vawy = -0.5 mi / h

Explanation:

We using the sum of vectors, we use the indexes ‘a’ for the plane, ‘g’ for the land ‘w’ for the wind,

          = +  

          = +

To facilitate the calculation we decompose with respect to xy coordinate system

          =   cos 30

         =   sin30

         Vwgx = Vwd cos 30  

         Vwgx = Vwd sin30  

         Vmgx = 1.00 cos 30  

         Vmgx = 0.866 mi / h  

         Vmgy = 1.00 sin30  

         Vwgy = 0.5 mi / h  

Let's find the resulting components  

         Vawx = 3.00 -0.866  

         Vawx = 2,134 mi / h  

         Vawy = 0 - 0.5  

         Vawy = -0.5 mi / h

Let's use Pythagoras' theorem  

        Vaw2 = Vawx2 + Vawy2  

        Vaw = Ra Vawx2 + Vawy2  

        Vaw = ra 2,134 2 + 0.52  

        Vaw = 2.19 mi / h  

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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the answer is b

explanation: