Use your graphs to measure the time required for the voltage across the capacitor to achieve 63% of the total change in voltage. that is, for charging, the time needed to rise from 0 volts to 63% of the final voltage. (note your final voltage may not be exactly 5 v.) for discharging, it is the time required to fall from the initial voltage to a value just 37% of the initial value. compare these times with the calculated time constants. calculate the maximum amount of charge stored on the capacitor. (hint: what equation can you use to relate the maximum potential difference across the capacitor to the maximum charge stored on it? ) make sure your answer for the maximum charge includes your uncertainty in your answer.