In order to calculate the weight of an object sitting on the earth’s surface, one would use the following formula: fg = gmem r 2 where g = 6.674 × 10−11 m3 kg s2 is the universal gravitational constant, me = 5.97 × 1024 kg is the mass of the earth (also a constant), r is the radius of the earth at the object’s location (measured in m), and m = the mass of the object (measured in kg). calculate your weight (to the correct number of significant figures) using this formula if your mass is 9.01 × 104 g and the radius of the earth at the object’s location is 6.382 × 106 m. use unit algebra to express the unit for weight as some combination of the metric system’s standard units for mass, length, and time.

The weight is 881.397 N

Explanation:

You have to replace the values of G, ME, r and m in the given formula to calculate the weight

The mass of the object (in this case, your mass) should be replaced in kg, so you have to covert it to kg

Is known that 1000g=1kg, so dividing the mass by 1000 you will obtain the mass is kg:

m =

Replacing the values in the formula:

Calculating the value of FG:

FG= 881.397

Now you have to use unit algebra to find the unit for weight. You have to replace just the units in the given formula:

FG=

Applying properties of exponential numbers and rational numbers:

where N is newton, the unit for force.

So, the weight (given by FG) is: 881.397 N

with 5 seconds, no, but over time if the police car stays at 65m/s ad the speeding car stays at 60, then obviously yes, but the answer to your question would be, no.

hope this : )