Adefibrillator containing a 18.4 μf capacitor is used to shock the heart of a patient by holding it to the patient's chest. just prior to discharging, the capacitor has a voltage of 13.2 kv across its plates. how much energy e is released into the patient, assuming no energy losses? e = j

The energy E is 1603.008 J.

Explanation:

Given that,

Capacitor = 18.4 μF

Voltage = 13.2 kV

We need to calculate the energy

Using formula of energy

.....(I)

We know that,

Put the value of Q in equation (I)

On integration

Put the value into the formula

Hence, The energy E is 1603.008 J.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.