Three people pull simultaneously on a stubborn donkey. jack pulls directly ahead of the donkey with a force of 77.3 n, jill pulls with 61.7 n in a direction 45° to the left, and jane pulls in a direction 45° to the right with 147 n. (since the donkey is involved with such uncoordinated people, who can blame it for being stubborn? ) find the magnitude of the net force the people exert on the donkey. magnitude of the net force: what is the direction of the net force? express this as the angle from straight ahead between 0° and 90°, with a positive sign for angles to the left and a negative sign for angles to the right.
direction of the net force: °

towards right so it is -15 degree

Explanation:

Net force in forward direction due to all three is given as

here we know that

Similarly in Y direction we will have

Now the net force on the donkey is given as

Now direction of force is given as

towards right so it is -15 degree

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts