Atime-varying net force acting on a 2.6 kg particle causes the object to have a displacement given by x = a + b t + d t2 + e t3 , where a = 1.1 m , b = 1.8 m/s, d = −3.1 m/s 2 , and e = 1.1 m/s 3 , with x in meters and t in seconds. find the work done on the particle in the first 4.4 s of motion. answer in units of j.

The answer is: 1913.5158 J

Explanation:

First we need to derivate the displacement equation:

Second, we need to know the 2nd Law of Newton:

So, we have:

Third, to calculate the work done on the particle we need the next equation:

Then, we have everything to replace in the variables(dx is replaced by the first derivative) :

And finally we have as a result:

W = 1913.5158 J