Arifle is aimed horizontally at a target 30 m away. the bullet hits the target 1.9 cm below the aiming point. what are the bullet’s a. time of flight? b. speed as it emerges from the rifle? 3.

0.0622 s

482.31 m/s

Explanation:

Given

target distance=30 m

Bullet hits the target 1.9 cm below

If we consider bullet motion to be projectile then

vertical distance traveled=1.9 cm

time travel to cover 1.9 cm is

here u is initial vertical velocity

Range =30 m

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr